Ingrid Senior

2022-03-03

What is the limit of the function algebraically, $\underset{x\to -5}{lim}=\frac{{x}^{2}-25}{x+5}$

Daisie Benitez

Beginner2022-03-04Added 5 answers

Step 1

Assuming:$\underset{x\to -5}{lim}\left[\frac{{x}^{2}-25}{x+5}\right]$

Plugging$x=-5$ into the numerator and denominator (which are both continuous functions) gives $\frac{0}{0}$

Try to algebraically simplify.

$\left[\frac{{x}^{2}-25}{x+5}\right]=\left[\frac{(x-5)(x+5)}{x+5}\right]=x-5$

when x not equal to -5

$\underset{x\to -5}{lim}\left[\frac{{x}^{2}-25}{x+5}\right]=\underset{x\to -5}{lim}(x-5)=-5-5=-10$

Assuming:

Plugging

Try to algebraically simplify.

when x not equal to -5

$\frac{20b}{{\left(4{b}^{3}\right)}^{3}}$

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