Naeem Stanton

2022-02-16

I know that all meromorphic functions on $\mathbb{C}P{P}^{1}$ are rational functions. However, Im

Pooja Copeland

Note that
$\mathbb{C}=\left\{\left[z:1\right]\mid z\in \mathbb{C}\right\}\subseteq \mathbb{C}P{P}^{1}$
Hence you can identify ${F}_{A}$ with a rational function ${f}_{A}$ given by
${f}_{A}\left(z\right)={F}_{A}\left(\left[z:1\right]\right)$
Then
${F}_{A}\left(z\right)=\frac{az+b}{cz+d}$.

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