"How do you multiply (2p3+5p2−4)(3p+1)?" solved and explained

Secondary
Algebra
Algebra II
Polynomial factorization

fumefluosault7pa

Answered question

2022-02-11

How do you multiply

(2 p^{3} + 5 p^{2} - 4) (3 p + 1)

Answer & Explanation

misseymayhemipv

Beginner2022-02-12Added 11 answers

Explanation:

(2 p^{3} + 5 p^{2} - 4) (3 p + 1) = 2 p^{3} \times 3 p + 5 p^{2} \times 3 p - 4 \times 3 p + 2 p^{3} + 5 p^{2} - 4

= 6 p^{4} + 15 p^{3} - 12 p + 2 p^{3} + 5 p^{2} - 4

(2 p^{3} + 5 p^{2} - 4) (3 p + 1) = 6 p^{4} + 17 p^{3} + 5 p^{2} - 12 p - 4

Keenan Mora

Beginner2022-02-13Added 11 answers

By multiplying each part of the right hand bracket, 3p and 1, by each part of the left hand bracket,

2 p^{3}, 5 p^{2}

and -4 you get:

6 p^{4} + 15 p^{3} - 12 p + 2 p^{3} + 5 p^{2} - 4

which simplifies to:

6 p^{4} + 17 p^{3} + 5 p^{2} - 12 p - 4

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