How do you find the product of $3{p}^{4}(4{p}^{4}+7{p}^{3}+4p+1)$?

Answer & Explanation

falwennaf5c7

Beginner2022-02-12Added 7 answers

Explanation:
Multiply $3{p}^{4}$ by each term in parenthesis:
$(3{p}^{4}\cdot 4{p}^{4})+(3{p}^{4}\cdot 7{p}^{3})+(3{p}^{4}\cdot 4p)+(3{p}^{4}\cdot 1)\to$ $(3{p}^{4}\cdot 4{p}^{4})+(3{p}^{4}\cdot 7{p}^{3})+(3{p}^{4}\cdot 4{p}^{1})+(3{p}^{4}\cdot 1)\to$
Then multiply the numbers and the x terms using the rules for exponents:
$12{p}^{4+4}+21{p}^{4+3}+12{p}^{4+1}+3{p}^{4}\to$ $12{p}^{8}+21{p}^{7}+12{p}^{5}+3{p}^{4}$