"How do you multiply (m2−4∓+p2)(m2+4∓−p2)?" was answered by our community

Secondary
Algebra
Algebra II
Polynomial factorization

cyrsvab

Answered question

2022-02-04

How do you multiply

(m^{2} - 4 \mp + p^{2}) (m^{2} + 4 \mp - p^{2})

Answer & Explanation

Addison Matthews

Beginner2022-02-05Added 13 answers

Explanation:

(m^{2} - 4 \mp + p^{2}) (m^{2} + 4 \mp - p^{2})

= m^{2} (m^{2} + 4 \mp - p^{2}) - 4 \mp (m^{2} + 4 \mp - p^{2}) + p^{2} (m^{2} + 4 \mp - p^{2})

= m^{4} + 4 m^{3} p - p^{2} m^{2} - 4 m^{3} p - 16 m^{2} p^{2} + 4 \mp^{3} + p^{2} m^{2} + 4 \mp^{3} - p^{4}

= m^{4} - 16 m^{2} p^{2} + 8 \mp^{3} - p^{4}

stefjumnmt

Beginner2022-02-06Added 14 answers

One can use formula

(a - b) (a + b) = a^{2} - b^{2}

as follows:

(m^{2} - 4 \mp + p^{2}) (m^{2} + 4 \mp - p^{2})

= (m^{2} - (4 \mp - p^{2})) (m^{2} + (4 \mp - p^{2})))

= {(m^{2})}^{2} - {(4 \mp - p^{2})}^{2}

= m^{4} - (16 m^{2} p^{2} - 8 \mp^{3} + p^{4})

= m^{4} - 16 m^{2} p^{2} + 8 \mp^{3} - p^{4}

Do you have a similar question?

Recalculate according to your conditions!

Didn't find what you were looking for?

Product

Company

Connect with us

Get Plainmath App

Google Play

Louki Akrita, 23, Bellapais Court, Flat/Office 46, 1100, Nicosia, Cyprus

Cyprus reg.number: ΗΕ 419361

E-mail us: support@plainmath.net

Our Service is useful for:

Plainmath is a platform aimed to help users to understand how to solve math problems by providing accumulated knowledge on different topics and accessible examples. Plainmath.net is owned and operated by RADIOPLUS EXPERTS LTD.