Dalia Morales

2022-02-03

What is the standard form of $y=\left(\frac{1}{5}{x}^{2}-\frac{1}{12}\right)\left(\frac{1}{3}x+\frac{3}{8}\right)$?

mixtyggc

Explanation:
Given: $y=\left(\frac{1}{5}{x}^{2}-\frac{1}{12}\right)\left(\frac{1}{3}x+\frac{3}{8}\right)$
$y=\frac{1}{5}{x}^{2}\left(\frac{1}{3}x+\frac{3}{8}\right)+\left(-\frac{1}{12}\right)\left(\frac{1}{3}x+\frac{3}{8}\right)$
$y=\left(\frac{1}{15}{x}^{3}+\frac{3}{40}{x}^{2}\right)+\left(-\frac{1}{36}x-\frac{3}{96}\right)$
$y=\frac{1}{15}{x}^{3}+\frac{3}{40}{x}^{2}-\frac{1}{36}x-\frac{3}{96}$
Result:
$y=\frac{1}{15}{x}^{3}+\frac{3}{40}{x}^{2}-\frac{1}{36}x-\frac{3}{96}$

Do you have a similar question?