What is the standard form of y=(2+x2)(x−7)−(2x+3)2?

Question

Reagan Blair · Accepted Answer

Explanation:
the first thing to do is multiply out the pairs of brackets

(2 + x^{2}) (x - 7) = 2 (x - 7) + x^{2} (x - 7) = 2 x - 14 + x^{3} - 7 x^{2}

and

{(2 x + 3)}^{2} = (2 x + 3) (2 x + 3) = 2 x (2 x + 3) + 3 (2 x + 3)

= 4 x^{2} + 6 x + 6 x + 9

expression now becomes

2 x - 14 + x^{3} - 7 x^{2} - (4 x^{2} + 12 x + 9)

= 2 x - 14 + x^{3} - 7 x^{2} - 4 x^{2} - 12 x - 9

= x^{3} - 11 x^{2} - 10 x - 23

Result:

x^{3} - 11 x^{2} - 10 x - 23

Answered question