What is the standard form of y=(-x-5)(8x-2)?

Explanation:
Standard form for an expression is listing the terms , beginning with the term with the highest exponent of the variable followed by decreasing exponents until the last term , usually a constant.
begin by distributing the brackets.
Each term in the 2nd bracket must be multiplied by each term in the 1st.This can be done as follows.
thus: -x(8x-2)-5(8x-2)
hence ${\displaystyle -8x^2+2x-40x+10=-8x^2-38x+10}$
This expression is in standard form.
Answer:
${\displaystyle -8x^2-38x+10}$