Julianne Martinez

2022-02-03

What is the standard form of y=(-x-5)(8x-2)?

supletiv2i4

Expert

Explanation:
Standard form for an expression is listing the terms , beginning with the term with the highest exponent of the variable followed by decreasing exponents until the last term , usually a constant.
begin by distributing the brackets.
Each term in the 2nd bracket must be multiplied by each term in the 1st.This can be done as follows.
thus: -x(8x-2)-5(8x-2)
hence $-8{x}^{2}+2x-40x+10=-8{x}^{2}-38x+10$
This expression is in standard form.
$-8{x}^{2}-38x+10$