What is the standard form of y=2(x-3)(x-2)(3x-5)?

Question

ribejat1f3 · Accepted Answer

Explanation: In general the standard form of a polynomial is

y = a_{n} x^{n} + a_{n - 1} x^{n - 1} + \dots + a_{2} x^{2} + a_{1} x^{1} + a_{0}

To achieve the standard form, multiply out the expression

y = 2 (x - 3) (3 x^{2} - 6 x - 5 x + 10)

y = 2 (3 x^{3} - 11 x^{2} + 10 x - 9 x^{2} + 33 x - 30)

y = 2 (3 x^{3} - 20 x^{2} + 43 x - 30)

y = 6 x^{3} - 40 x^{3} + 86 x - 60

Answer:

y = 6 x^{3} - 40 x^{3} + 86 x - 60

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