What is the leading term, leading coefficient, and degree of this polynomial f(x)=x2(2)+x−5?

Explanation:
${\displaystyle f\left(x\right)=x^2\left(\sqrt{2}\right)+x-5}$
We can write this as:
${\displaystyle f\left(x\right)=\sqrt{2}{x}^2+x+5}$
This is a quadratic in standard form: ${\displaystyle a{x}^2+bx+c}$
Where: ${\displaystyle a=\sqrt{2}}$, b=1 and c=5
Hence, Leading term: ${\displaystyle \sqrt{2}{x}^2}$ and leading coefficient: ${\displaystyle \sqrt{2}}$.
Also, a quadratic function is of degree 2, since the leading term is of x to the power 2.
Leading term ${\displaystyle \sqrt{2}{x}^2}$, Leading coefficient: ${\displaystyle \sqrt{2}}$, Degree 2.