iocasq4

2022-01-28

How do you write $y-2=\frac{1}{7}x$ in standard form?

sjkuzy5

Beginner2022-01-29Added 11 answers

Explanation:

It's almost already in standard form: you obtain the standard form when you write your equality as y=f(x), for a certain f(x).

If we add 2 to both sides, we isolate the y term, since we get

$y-2+2=\frac{1}{7}x+2$

and simplifying

$y=\frac{1}{7}x+2$

It's almost already in standard form: you obtain the standard form when you write your equality as y=f(x), for a certain f(x).

If we add 2 to both sides, we isolate the y term, since we get

and simplifying

$\frac{20b}{{\left(4{b}^{3}\right)}^{3}}$

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