Isis Solis

2022-01-30

How do you write a polynomial function in standard form with the zeroes x=-2,1,4?

Flickkorbma

Expert

f(x)=(x+2)(x-1)(x-4)
$=\left({x}^{2}+x-2\right)\left(x-4\right)$
$=\left({x}^{2}+x-2\right)x-\left({x}^{2}+x-2\right)4$
$={x}^{3}+{x}^{2}-2x-4{x}^{2}-4x+8$
$={x}^{3}-3{x}^{2}-6x+8$

Jude Carpenter

Expert

x=-2,1,4
f(x)=[x-(-2)][x-1][x-4]
f(x)=(x+2)(x-1)(x-4)
$\left({x}^{2}-x+2x-2\right)\left(x-4\right)$
$\left({x}^{2}+x-2\right)\left(x-4\right)$
$x\left({x}^{2}+x-2\right)-4\left({x}^{2}+x-2\right)$
$={x}^{3}+{x}^{2}-2x-4{x}^{2}-4x+8$
$={x}^{3}-3{x}^{2}-6x+8$

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