How do you write in standard form an equation of the line with the slope...

Explanation:
First off you have to know the standard form formula which is:
y=mx+b
Plug in the slope and the points (x,y) to get b
y=mx+b
2=-4(2)+b
2=-8+b
Next, you add 8 to both sides to get b alone:
10=b
Plug your slope and b value into the standard formula

Explanation:
the equation of a line in standard form is.
Ax+By=C
where A is a positive integer and B, C are integers
obtain the equation in point-slope form and rearrange into standard form
${\displaystyle y-y_1=m(x-x_1)}$
where m is the slope and ${\displaystyle (x_1,y_1)}$ a point on the line
here m=-4 and ${\displaystyle (x_1,y_1)=(2,2)}$
${\displaystyle \Rightarrow y-2=-4(x-2)\leftarrow }$ in point-slope form
${\displaystyle \Rightarrow y-2=-4x+8}$
add 4x to both sides
${\displaystyle \Rightarrow 4x+y-2=8}$
add 2 to both sides
${\displaystyle \Rightarrow 4x+y=10\leftarrow }$ in standard form