sentidosin0q

Answered

2022-01-30

How do you write in standard form an equation of the line with the slope -4 through the given point (2,2)?

Answer & Explanation

ocretz56

Expert

2022-01-31Added 16 answers

Explanation:

First off you have to know the standard form formula which is:

y=mx+b

Plug in the slope and the points (x,y) to get b

y=mx+b

2=-4(2)+b

2=-8+b

Next, you add 8 to both sides to get b alone:

10=b

Plug your slope and b value into the standard formula

First off you have to know the standard form formula which is:

y=mx+b

Plug in the slope and the points (x,y) to get b

y=mx+b

2=-4(2)+b

2=-8+b

Next, you add 8 to both sides to get b alone:

10=b

Plug your slope and b value into the standard formula

logik4z

Expert

2022-02-01Added 8 answers

Explanation:

the equation of a line in standard form is.

Ax+By=C

where A is a positive integer and B, C are integers

obtain the equation in point-slope form and rearrange into standard form

$y-{y}_{1}=m(x-{x}_{1})$

where m is the slope and$({x}_{1},{y}_{1})$ a point on the line

here m=-4 and$({x}_{1},{y}_{1})=(2,2)$

$\Rightarrow y-2=-4(x-2)\leftarrow$ in point-slope form

$\Rightarrow y-2=-4x+8$

add 4x to both sides

$\Rightarrow 4x+y-2=8$

add 2 to both sides

$\Rightarrow 4x+y=10\leftarrow$ in standard form

the equation of a line in standard form is.

Ax+By=C

where A is a positive integer and B, C are integers

obtain the equation in point-slope form and rearrange into standard form

where m is the slope and

here m=-4 and

add 4x to both sides

add 2 to both sides

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