sentidosin0q

2022-01-30

How do you write in standard form an equation of the line with the slope -4 through the given point (2,2)?

ocretz56

Expert

Explanation:
First off you have to know the standard form formula which is:
y=mx+b
Plug in the slope and the points (x,y) to get b
y=mx+b
2=-4(2)+b
2=-8+b
Next, you add 8 to both sides to get b alone:
10=b
Plug your slope and b value into the standard formula

logik4z

Expert

Explanation:
the equation of a line in standard form is.
Ax+By=C
where A is a positive integer and B, C are integers
obtain the equation in point-slope form and rearrange into standard form
$y-{y}_{1}=m\left(x-{x}_{1}\right)$
where m is the slope and $\left({x}_{1},{y}_{1}\right)$ a point on the line
here m=-4 and $\left({x}_{1},{y}_{1}\right)=\left(2,2\right)$
$⇒y-2=-4\left(x-2\right)←$ in point-slope form
$⇒y-2=-4x+8$
$⇒4x+y-2=8$
$⇒4x+y=10←$ in standard form