Inyalan0

2022-01-17

A rocket is fired upward from the ground with an initial velocity off 220 feet per second. Neglecting air resistance, the height of the rocket at any time t can be described in feet by the polynomial-16t to the power of 2+220t. Find the height of the rocket at t=7 seconds.

usaho4w

Expert

Step 1
Definition used -
Value of function at a point -
If we have to find the value of function f(x) at x =a then, We will substitute a in place of x in given function. So value of function at x = a is given by f(a).
Step 2
Given -
$h\left(t\right)=-16{t}^{2}+220t$
We have to find height when t = 7
So we will substitute t = 7 in h(t)
$h\left(7\right)=-16{\left(7\right)}^{2}+220\left(7\right)=756$ feet
Step 3
Answer - Height of rocket at t= 7 seconds is 756 feet.

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