Inyalan0

Answered

2022-01-17

A rocket is fired upward from the ground with an initial velocity off 220 feet per second. Neglecting air resistance, the height of the rocket at any time t can be described in feet by the polynomial-16t to the power of 2+220t. Find the height of the rocket at t=7 seconds.

Answer & Explanation

usaho4w

Expert

2022-01-18Added 39 answers

Step 1

Definition used -

Value of function at a point -

If we have to find the value of function f(x) at x =a then, We will substitute a in place of x in given function. So value of function at x = a is given by f(a).

Step 2

Given -

$h\left(t\right)=-16{t}^{2}+220t$

We have to find height when t = 7

So we will substitute t = 7 in h(t)

$h\left(7\right)=-16{\left(7\right)}^{2}+220\left(7\right)=756$ feet

Step 3

Answer - Height of rocket at t= 7 seconds is 756 feet.

Definition used -

Value of function at a point -

If we have to find the value of function f(x) at x =a then, We will substitute a in place of x in given function. So value of function at x = a is given by f(a).

Step 2

Given -

We have to find height when t = 7

So we will substitute t = 7 in h(t)

Step 3

Answer - Height of rocket at t= 7 seconds is 756 feet.

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