Solve the equation by factoring. 2x^{2}-5x-3=0

Cynthia Bell

Cynthia Bell

Answered question

2021-12-31

Solve the equation by factoring.
2x25x3=0

Answer & Explanation

otoplilp1

otoplilp1

Beginner2022-01-01Added 41 answers

Step 1
The given equation is,
2x25x3=0
The given equation can be solved using factorization.
Step 2
On solving the given equation, we get
2x25x3=0
2x26x+x3=0
2x(x-3)+1(x-3)=0
(2x+1)(x-3)=0
Hence,
2x+1=0
2x=-1
x=12...(i)
And,
x-3=0
x=3...(ii)
Therefore, the solution of the given equation is -1/2 and 3.
levurdondishav4

levurdondishav4

Beginner2022-01-02Added 38 answers

In order to factor this you need to multiply -3 by 2 to get -6, the two factors of this problem will add to give you -5 and multiply to give you -6. once you have the factors you must divide the expression by 2.
2x25x3=0
next (2x-6)(2x+1)/2
pull out a 2 from (2x-6)
2(x-3)(2x+1)/2
the 2'scancel
and your solution is (x-3)(2x+1) the zeros are 3, -1/2

Vasquez

Vasquez

Expert2022-01-09Added 669 answers

1.Open up brackets: ()() 2.Break up the first term: (2x)(x) 3.Break up the 3rd term such that the product of the x term and non x term given the middle number: (2x+1)(x-3)

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