Solve the following quadratic equation by factorization. 2xx−3+12x+3+3x+9(x−3)(2x+3)=0

PEEWSRIGWETRYqx

PEEWSRIGWETRYqx

Answered

2021-12-18

Solve the following quadratic equation by factorization.
2xx3+12x+3+3x+9(x3)(2x+3)=0

Answer & Explanation

Elaine Verrett

Elaine Verrett

Expert

2021-12-19Added 41 answers

Given
2xx3+12x+3+3x+9(x3)(2x+3)=0
Step by step solution
2x(2x+3)+1(x3)+3x+4(x3)(2x+3)
4x2+6x+x3+3x+9=0
4x2+10x+6=0
2(2x2+5x+3)=0
2x2+5x+3=0
Complete Solution
2x2+5x+3=0
2x2+2x+3x+3=0
2x(x+1)+3(x+1)=0
(x+1)(2x+3)=0
x=1
or
2x+3=0
x=32
Paul Mitchell

Paul Mitchell

Expert

2021-12-20Added 40 answers

Step 1
Given equation is 2xx3+12x+3+3x+9(x3)(2x+3)=0
Upon simplification this can be written as:
2x(2x+3)+1(x3)+3x+9(x3)(2x+3)=0
Taking denominator to the right hand side
2x(2x+3)+1(x-3)+3x+9=0
Step 2
4x2+6x+x3+3x+9=0
4x2+10x+6=0
4x2+4x+6x+6=0
4x(x+1)+6(x+1)=0
(4x+6)(x+1)=0
4x+6=0 or x+1=0
4x=6 or x=-1
x=64 or x=-1
x=32 or x=-1
Therefore x=-1.5 or -1
nick1337

nick1337

Expert

2021-12-28Added 573 answers

Step 1
Factorization method:-
2xx3+12x+3+3x+9(x3)(2x+3)=02x(2x+3)+(x3)+3x+9(x3)(2x+3)=04x2+6x+x3+3x+9=04x2+10x+6=04x2+4x+6x+6=04x(x+1)+6(x+1)=0(x+1)(4x+6)=0x+1=0 or 4x+6=0x=1,32
But x32
Step 2
Thus, x=-1 is the solution of the given equation

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get your answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?