Solve the following quadratic equation by factorization method : x2+3x−(a2+a−2)=0

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Solve the following quadratic equation by factorization method :  x2+3x−(a2+a−2)=0

sukljama2 · Accepted Answer

Step 1  To solve the quadratic equation using factorization method.  Step 2  x2+3x−(a2+a−2)=0  x2+3x−(a2+2a−a−2)=0  x2+3x−(a(a+2)−1(a+2))=0  x2+3x−((a+2)(a−1))=0  x2+((a+2)−(a−1))x−((a+2)(a−1))=0  x2+(a+2)x−(a−1)x−(a+2)(a−1)=0  x(x+(a+2))-(a-1)(x+(a+2))=0  (x+(a+2))(x-(a-1))=0  x+(a+2)=0 or x-(a-1)=0  x=-a-2, x=a-1

John Koga · Accepted Answer

Step 1 Given  a2b2x2+b2x−a2x−1=0  Step 2 solving  (a2b2x2+b2x)−(a2x+1)=0  (a2x+1)b2x−(a2x+1)=0  (a2x+1)(b2x−1)=0  a2x+1=0,b2x−1=0  a2x=−1,b2x=1  x=1a2,x=1b2

Solve the following quadratic equation by factorization method : x2+3x−(a2+a−2)=0

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