Factor the quadratic polynomials. x2−4x−12

Question

Factor the quadratic polynomials.  x2−4x−12

MoxboasteBots5h · Accepted Answer

The given quadratic polynomial is x2−4x−12.  It is factored as follows.  x2−4x−12=x2−6x+2x−12  =x(x-6)+2(x-6)  =(x+2)(x-6)

Joseph Fair · Accepted Answer

The given equation is:  x2−4x−12  ⇒x2−4x=12  Thus,  x2−4x=12  ⇒x2−4x−12=0  The product of the second degree term and the constant is −12x2. Factors of −12x2 that sum to -4x are -6x and 2x. Thus,  Factorizing which we get,  x2−4x−12=0  ⇒x2−6x+2x−12=0  ⇒x(x−6)+2(x−6)=0  ⇒(x−6)(x+2)=0  The required values of x are 6 and -2.

Factor the quadratic polynomials. x2−4x−12

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