Find all zeros of the polynomial. P(x)=x^{2}+2x^{2}+4x+8

Irrerbthist6n

Irrerbthist6n

Answered question

2021-12-12

Find all zeros of the polynomial.
P(x)=x2+2x2+4x+8

Answer & Explanation

zesponderyd

zesponderyd

Beginner2021-12-13Added 41 answers

Step 1
Given: p(x)=x2+2x2+4x+8
We know that zeros of quadratic equation (ax2+bx+c=0) is given by
x=b±b24ac2a
Step 2
So, first we simplify given expression then equate it with zero and by using equation(1) find zeros of it
So,
x2+2x2+4x+8=0
3x2+4x+8=0
x=4±424(3)(8)2(3)
x=4±16966
x=4±806
x=4±45i6
x=2±25i3
Hence, zeros of given polynomial are x=2±25i3

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