Express as a polynomial. (r2+8r−2)(r2+3r−1)

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Matthew Rodriguez · Accepted Answer

Step 1  Given expression:  (r2+8r−2)(r2+3r−1)  Step 2  Consider,  (r2+8r−2)(r2+3r−1)=r2(r2+3r−1)+8r(r2+3r−1)−2(r2+3r−1)...Use the distributive property.  =[r2(r2)+r2(3r)+r2(−2)]+[(8r)(r2)+(28r)(3r)+(8r)(−2)]−[2r2+(2)(3r)−(2)(1)]  =r4+3r3−2r2+8r3+24r2−16r−2r2−6r+2  =r4+(3r3+8r3)+(−2r2+24r2−2r2)+(−16r−6r)+2...Collect like terms together.  =r4+11r3+20r2−22r+2  Thus,  (r2+8r−2)(r2+3r−1)=r4+11r3+20r2−22r+2

Express as a polynomial. (r2+8r−2)(r2+3r−1)

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