Solve the given quadratic equation by factorization method. 4x2−2(a2+b2)x+a2b2=0

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Solve the given quadratic equation by factorization method.  4x2−2(a2+b2)x+a2b2=0

servidopolisxv · Accepted Answer

Step 1 Given  4x2−2(a2+b2)x+a2b2=0  Step 2 Solving  4x2−2a2x−2b2x+a2b2=0  (4x2−2a2x)−(2b2x−a2b2)=0  2x(2x−a2)−b2(2x−a2)=0  (2x−b2)(2x−a2)=0  2x−b2=0;2x−a2=0  2x=b2;2x=a2  x=b22;x=a22  ∴x=a22,b22

Solve the given quadratic equation by factorization method. 4x2−2(a2+b2)x+a2b2=0

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