The scoring of modern IQ tests is such that Intelligence Quotients (IQs) have No

Suman Cole

Suman Cole

Answered question

2021-11-10

The scoring of modern IQ tests is such that Intelligence Quotients (IQs) have Normal distribution with μ=100 and σ=15
a) What percent of people have IQ less than 80?
b) What percent of people have IQ greater than 120?
c) Mensa International is a non-profit organization that accepts only people with IQ within the top 2%.
What level of IQ qualifies one to be a member of Mensa?

Answer & Explanation

Nathanael Webber

Nathanael Webber

Skilled2021-11-11Added 117 answers

Step 1
Given:
μ=Mean=100
σ=Standard deviation=15
a) The z-score is the value decreased by the mean, divivded by the standard deviation.
z=xμσ=80100151.33
Determine the corresponding probability using the normal probability table in the appendix. P(Z<1.33) is given in the row starting with -1.3 and in the cilumn starting with 0.03 of the standard normal probability table in the appendix.
P(X<80)=P(Z<1,33)
=0.0918
=9.18%
Thus 9.18% of the people are expected to have an IQ less than 80.
Step 2
b) The z-score is the value decreased by the mean, divivded by the standard deviation.
z=xμσ=120100151.33
Determine the corresponding probability using the normal probability table in the appendix. P(Z<1.33) is given in the row starting with 1.3 and in the cilumn starting with 0.03 of the standard normal probability table in the appendix.
P(X>120)=P(Z>1,33)
=1P(Z<1.33)
=10.9082
=9.18% Thus 9.18% of the people are expected to have an IQ less than 120.
c) The boundary of the top 2% has the property that 100%2%=98% of the people below this boundary.
Determine the critical value corresponding with a probability of 98% or 0.98 using the normal probability table in the appendix. We note that the closest probability 0.9798 is given in the row starting with "2.0" and in the column starting with "0.05:
z=2.05
The corresponding value is then obtained by adding the product of the z-score and the standard deviation to the mean:
x=μ+zσ=100+2.05(15)=130.75
Thus the top 2% have an IQ of at least 130.75.

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