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Logarithms
Globokim8
2021-11-09
Faiza Fuller
Skilled2021-11-10Added 108 answers
Step 1 Given: Let y=ln(1e) To Find:To assess the provided expression.Step 2 Solution: y=ln(1e) We know that ln(ab)=lna−lnb (Properties of logarithms) ⇒y=ln1−ln(e) Since ln1=0 ⇒y=0−ln(e) y=−ln(e)12 We know that lnxn (Properties of logarithms) ⇒y=−12lne Since lne=1 ⇒y=−12×1 y=−12 Hence ln(1e)=−12
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