EunoR

2021-10-17

A given polynomial has a root of x = 3, an zero of x = -2, and an x-intercept of x = -1.

The equation of this polynomial in factored form would be f(x) =

The equation of this polynomial in standard form would be f(x) =

The equation of this polynomial in factored form would be f(x) =

The equation of this polynomial in standard form would be f(x) =

Talisha

Skilled2021-10-18Added 93 answers

Step 1

Zeros, roots, and x-intercepts are all names for values that make a function equal to zero.

Given, a polynomial, f(x), has a root of x = 3, a zero of x = -2, and an x-intercept of x = -1.

Step 2

1. The equation of this polynomial in factored form would be :

f(x) = (x-3)(x-(-2))(x-(-1))

$\Rightarrow f\left(x\right)=(x-3)(x+2)(x+1)$

2. The equation of this polynomial in standard form would be :

$f\left(x\right)=(x-3)({x}^{2}+3x+2)$

$\Rightarrow f\left(x\right)={x}^{3}+3{x}^{2}+2x-3{x}^{2}-9x-6$

$\Rightarrow f\left(x\right)={x}^{3}-7x-6$

Zeros, roots, and x-intercepts are all names for values that make a function equal to zero.

Given, a polynomial, f(x), has a root of x = 3, a zero of x = -2, and an x-intercept of x = -1.

Step 2

1. The equation of this polynomial in factored form would be :

f(x) = (x-3)(x-(-2))(x-(-1))

2. The equation of this polynomial in standard form would be :

$\frac{20b}{{\left(4{b}^{3}\right)}^{3}}$

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