EunoR

Answered question

2021-10-17

A given polynomial has a root of x = 3, an zero of x = -2, and an x-intercept of x = -1.
The equation of this polynomial in factored form would be f(x) =
The equation of this polynomial in standard form would be f(x) =

Answer & Explanation

Talisha

Skilled2021-10-18Added 93 answers

Step 1
Zeros, roots, and x-intercepts are all names for values that make a function equal to zero.
Given, a polynomial, f(x), has a root of x = 3, a zero of x = -2, and an x-intercept of x = -1.
Step 2
1. The equation of this polynomial in factored form would be :
f(x) = (x-3)(x-(-2))(x-(-1))
$⇒f\left(x\right)=\left(x-3\right)\left(x+2\right)\left(x+1\right)$
2. The equation of this polynomial in standard form would be :
$f\left(x\right)=\left(x-3\right)\left({x}^{2}+3x+2\right)$
$⇒f\left(x\right)={x}^{3}+3{x}^{2}+2x-3{x}^{2}-9x-6$
$⇒f\left(x\right)={x}^{3}-7x-6$

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