Solve the equation. ln⁡x=1−ln⁡(x+2)

Question

Solve the equation.   ln⁡x=1−ln⁡(x+2)

unessodopunsep · Accepted Answer

Step 1 given, ln⁡x=1−ln⁡(x+2) Step 2 ln⁡x=1−ln⁡(x+2) log⁡x+log⁡(x+2)=1 log⁡[x(x+2)]=1 x(x+2)=e x2+2x−e=0 applying quadratic formula, x=−b±b2−4ac2a =−2±22−4×1×(−e)2 =−2±21+e2 =−1±1+e hence x=−1+1+e or x=−1−1+e

Solve the equation. ln⁡x=1−ln⁡(x+2)

Answered question

Answer & Explanation