tricotasu

2021-09-11

The given equation involves a power of the variable. Find all real solutions of the equation.
$2{x}^{\frac{5}{3}}+64=0$

Aniqa O'Neill

Step 1
The given equation is $2{x}^{\frac{5}{3}}+64=0$
Step 2
$2{x}^{\frac{5}{3}}+64=0$
$2{x}^{\frac{5}{3}}=-64$
${x}^{\frac{5}{3}}=-32$
${\left({x}^{\frac{5}{3}}\right)}^{\frac{1}{5}}={\left(-32\right)}^{\frac{1}{5}}$
${x}^{\frac{1}{3}}=-2$
$\left({x}^{\frac{1}{3}}\right)={\left(-2\right)}^{3}$
x=-8

Jeffrey Jordon