Given: E(t)=L(t)+C(t). E(t)=ksin^2(2piFt)+kcos^2(2piFt). Prove that E is a constant function, if k is constant.

BenoguigoliB

BenoguigoliB

Answered question

2021-09-09

Given:
E(t)=L(t)+C(t)
E(t)=ksin2(2πFt)+kcos2(2πFt)
Prove that E is a constant function, if k is constant.

Answer & Explanation

Nathanael Webber

Nathanael Webber

Skilled2021-09-10Added 117 answers

E(t)=L(t)+C(t)
E(t)=ksin2(2πFt)+kcos2(2πFt)
Factor k:
E(t)=k[sin2(2πFt)+kcos2(2πFt)]
sin2x+cos2x=1
E(t)=k(1)
E(t)=k
Since k is constant, E is a constant function.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?