preprekomW

2021-08-12

To find:

The period of a pendulum 3.5 ft long using$t=2\pi \sqrt{\frac{L}{32}}$ .

The period of a pendulum 3.5 ft long using

Laaibah Pitt

Skilled2021-08-13Added 98 answers

Step 1

The given model is time period is$t=2\pi \sqrt{\frac{L}{32}}$

The period of time t, in seconds, taken by the swing of a pendulum is given by the above formula.

where L is the length of the pendulum in feet.

Using this model, we can find the period of a pendulum 3.5 ft long.

Step 2

So,$L=3.5\text{}ft$ and $\pi =\frac{22}{7}$

Let us substitute in$t=2\pi \sqrt{\frac{L}{32}}$

$t=2\times \frac{22}{7}\times \sqrt{\frac{3.5}{32}}$

$t=2\times 3.14\times \sqrt{0.109375}$

$t=2\times 3.1428\times 0.3307$

$t=2.07$ seconds.

While rounding to the nearest tenth$t=2.1$ seconds

Therefore, the period of a pendulum 3.5 ft long is 2.1 seconds.

The given model is time period is

The period of time t, in seconds, taken by the swing of a pendulum is given by the above formula.

where L is the length of the pendulum in feet.

Using this model, we can find the period of a pendulum 3.5 ft long.

Step 2

So,

Let us substitute in

While rounding to the nearest tenth

Therefore, the period of a pendulum 3.5 ft long is 2.1 seconds.