Use your equation to determine the half-life ofthis type of Fodine, That is, find out how many days it will take for half of the original amount to be left. Show an algebraic solution using logs

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Viktor Wiley · Accepted Answer

To find the half life of iodine   (i.e) t= ? when P=P02= 102=5 grams of iodine P=10e−0.086t substitute P=5 in the above equation 5=10e−0.086t Dividing both sides by 10 we get, 510=e−0.086t  ⇒ e−0.086t= 12      e0.086t=2 Taking log on both sides we get, 0.086t=loge⁡2  ⇒ t= loge⁡20.086= 0.693100.086=8.0598 ≈ 8 Therefore it took 8 days for the iodine reduces to 5 grams

Use your equation to determine the half-life ofthis type of Fodine, That is, find out...

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