Solve by system of equations:5x+3y+z=-8x-3y+2z=2014x-2y+3z=20

Annette Arroyo

Annette Arroyo

Answered question

2021-05-28

Solve by system of equations:
5x+3y+z=8
x3y+2z=20
14x2y+3z=20

Answer & Explanation

Nathalie Redfern

Nathalie Redfern

Skilled2021-05-29Added 99 answers

Step 1
Given system of equations are
5x+3y+z=8...(1)
x3y+2z=20...(2)
14x2y+3z=20...(3)
Step 2
By subtracting 5 times equation (2) from equation (1), we get
5x+3y+z5(x3y+2z)=8100
18y9z=108
2yy=12...(4)
Step 3
By subtracting 14 times equation (2) from equation (3), we get
14x2y+3z14(x3+2z)=20280
40y25z=260
8y5z=52...(5)
Step 4
By subtracting 4 times equation (4) from equation (5), we get
8y5z4(2yz)=52+48
z=4
z=4
Step 5
By substituting z=4 in equation (4), we get value of y and then substituting values of y and z in equation (2), we get value of x
2yz=12
2y4=12
2y=8
y=4
x3y+2z=20
x3(4)+2(4)=20
x+12+8=20
x=0
Step 6
Answer: Solution is x=0,y=4 and z=4

Jeffrey Jordon

Jeffrey Jordon

Expert2021-11-19Added 2605 answers

Answer is given below (on video)

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