Micheal Mcconnell

2023-03-14

Find the remainder when the function $f\left(x\right)={x}^{3}-4{x}^{2}+12$ is divided by (x+2).

argueiro6rn

${x}^{3}-4{x}^{2}+12=g\left(x\right)\left(x+2\right)+r$
$x=-2$, ${\left(-2\right)}^{3}-4{\left(-2\right)}^{2}+12=g\left(x\right)\left(\left(-2\right)+2\right)+r$
$-12=0+r$
$r=-12$
$\frac{6}{4}=1$ + remaidr 2
$4×1+2=6$

Paxton Houston

$\text{here}\phantom{\rule{1ex}{0ex}}\left(x-a\right)=\left(x-\left(-2\right)\right)⇒a=-2$
$f\left(-2\right)={\left(-2\right)}^{3}-4{\left(-2\right)}^{2}+12=-12$

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