Sergio Heath

2023-02-24

What is the factorization of ${x}^{2}+7x-8$?
A) $\left(x-8\right)\left(x+1\right)$;
B)$\left(x+5\right)\left(x-9\right)$;
C)$\left(x+7\right)\left(x-2\right)$;
D)$\left(x+8\right)\left(x-1\right)$

antipornofsc2

The right answer is D (x+8)(x-1)
${x}^{2}+7x-8\phantom{\rule{0ex}{0ex}}={x}^{2}+8x-x-8\phantom{\rule{0ex}{0ex}}=x\left(x+8\right)-\left(x+8\right)\phantom{\rule{0ex}{0ex}}=\left(x+8\right)\left(x-1\right)$

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