Sergio Heath

2023-02-24

What is the factorization of ${x}^{2}+7x-8$?

A) $(x-8)(x+1)$;

B)$(x+5)(x-9)$;

C)$(x+7)(x-2)$;

D)$(x+8)(x-1)$

A) $(x-8)(x+1)$;

B)$(x+5)(x-9)$;

C)$(x+7)(x-2)$;

D)$(x+8)(x-1)$

antipornofsc2

Beginner2023-02-25Added 5 answers

The right answer is D (x+8)(x-1)

${x}^{2}+7x-8\phantom{\rule{0ex}{0ex}}={x}^{2}+8x-x-8\phantom{\rule{0ex}{0ex}}=x(x+8)-(x+8)\phantom{\rule{0ex}{0ex}}=(x+8)(x-1)$

${x}^{2}+7x-8\phantom{\rule{0ex}{0ex}}={x}^{2}+8x-x-8\phantom{\rule{0ex}{0ex}}=x(x+8)-(x+8)\phantom{\rule{0ex}{0ex}}=(x+8)(x-1)$