Identify the 42nd term of an arithmetic sequence where a1=-12 and a27=66.

litanijblm

litanijblm

Answered question

2022-12-08

Identify the 42nd term of an arithmetic sequence where a1=-12 and a27=66.

Answer & Explanation

vestirsmsl

vestirsmsl

Beginner2022-12-09Added 4 answers

Find the term of an arithmetic sequence:
The nth term of a arithmetic sequence is given by:
an=a1+n-1d,
where, a1 is the first term,
an is the nth term,
d is the common difference.
Put a1=12 ,n=27and a27=66 to find d:
a27=a1+(27-1)d66=-12+26·d26·d=66+12d=7826d=3
Now, the 42nd term is given by:
a42=a1+(42-1)3a42=-12+41·3a42=-12+123a42=111
Therefore, the 42nd term of the given arithmetic sequence is111.

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