How is discriminant related to real x? Solve for range of the function, y=(x^2+4x-1)/(3x^2+12x+20)

Kaylynn Cook

Kaylynn Cook

Answered question

2022-11-19

How is discriminant related to real x?
Solve for range of the function,
y = x 2 + 4 x 1 3 x 2 + 12 x + 20
Text book says, cross multiply and express the obtained equation as a quadratic equation in x
So I get ( 3 y 1 ) x 2 + ( 12 y 4 ) x + ( 20 y 1 ) = 0
Now it says find discriminant D, so we have,
D = 4 ( 3 y 1 ) ( 8 y + 3 )
Now it says, set D 0 as x is real. Wait what?
Isn't x R the domain for a quadratic function? Meaning "x" is always real? What does a discriminant got anything to do with x being real, when all discriminant tells us is whether or not the ROOTS are real? Help please.
To be more specific about my doubt, here's an edit.

Answer & Explanation

Phiplyrhypelw0

Phiplyrhypelw0

Beginner2022-11-20Added 24 answers

Initial Volume = 20l 20% juice
Let after 'x' l of 20% juice to removed. We are adding 70% juice of 'x' litreo
Total concetration of juice to 40%
Total volume is again 20 l.
\therefor ( 20 x ) has 20% juice
x has 70% juice
mixture has 40% juice
( 20 x ) 20 % + x × 70 % 20 × 100 = 40 ( 20 x 5 + 7 x 10 ) × 5 = 40 40 2 x + 7 x 10 = 8 40 + 5 x = 80 5 x = + 40 x = + 8
It means, after removing 8l of 20% juice.
we should add 70% juice to get 40% juice
Hayley Mcclain

Hayley Mcclain

Beginner2022-11-21Added 3 answers

Step 1
x 2 + 4 x 1 3 x 2 + 12 x + 20 = y
After cross multiplying, we obtain
( 3 y 1 ) x 2 + ( 12 y 4 ) x + ( 20 y + 1 ) = 0
Step 2
If the discriminant is nonnegative, then we can find real x as solution to the quadratic equation, and hence given a particular value of y that makes the discriminant nonnegative, we can find x that satisfy the original equation.
However, if the discriminant is negative, then x that satisfies the quadratic equation is not real.

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