Find two consecutive integers such that seven times the first integer plus the second is 81

Zackary Diaz

Zackary Diaz

Answered question

2022-11-05

Find two consecutive integers such that seven times the first integer plus the second is 81

Answer & Explanation

Nigerkamg5

Nigerkamg5

Beginner2022-11-06Added 20 answers

Let n stand for the first integer.
Then the second integer is n+1.
We are given: 7n+(n+1)=81
Subtract 1 from both sides to get:
8n=80
Divide both sides by 8 to get:
n=10
So the two integers are n=10 and n+1=11

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