Lewis Harvey

2021-02-19

$y=\frac{1}{2}x-2$
$6x+2y=10$

Nola Robson

Given that: $y=\frac{1}{2}x-2$
6x+2y=10
Substutiting the value of y from the first equation into the second equation we get $6x+2y=10\to 6x+2\left(\left(\frac{1}{2}x\right)-2\right)=10$
$\to 6x+x-4=10$
$\to 7x=10+4=14$
$\to x=\frac{14}{7}-2$
And hence $y=\left(\frac{1}{2}\right)x-2$
$=\frac{\frac{1}{2}}{2}-2$ =1-2 =-1
Hence the solution of the given equation is x=2, y=-1

Jeffrey Jordon