Given that: y=12x−2 6x+2y=10 Substutiting the value of y from the first equation into the second equation we get 6x+2y=10→6x+2((12x)−2)=10 →6x+x−4=10 →7x=10+4=14 →x=147−2 And hence y=(12)x−2 =122−2 =1-2 =-1 Hence the solution of the given equation is x=2, y=-1

"y=12x−2 6x+2y=10" was answered by our experts

Secondary
Algebra
Algebra I
Exponents and radicals

Lewis Harvey

Answered question

2021-02-19

y = \frac{1}{2} x - 2

6 x + 2 y = 10

Answer & Explanation

Nola Robson

Skilled2021-02-20Added 94 answers

Given that:

y = \frac{1}{2} x - 2

6x+2y=10
Substutiting the value of y from the first equation into the second equation we get

6 x + 2 y = 10 \to 6 x + 2 ((\frac{1}{2} x) - 2) = 10

\to 6 x + x - 4 = 10

\to 7 x = 10 + 4 = 14

\to x = \frac{14}{7} - 2

And hence

y = (\frac{1}{2}) x - 2

= \frac{\frac{1}{2}}{2} - 2

=1-2 =-1
Hence the solution of the given equation is x=2, y=-1

Jeffrey Jordon

Expert2021-08-11Added 2575 answers

Answered on video below

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