Consider the following system of equations: (x+1)^2[(p−l)^2+(q−m)^2] x+1)^2[(p−a)^2+(q−b)^2]=(a−l)^2+(b−m)^2=x^2[(a−l)^2+(b−m)^2] Find the value of p and q in terms of a,b,x,l and m, provided that x>0.

Dylan Nixon

Dylan Nixon

Answered question

2022-10-27

Consider the following system of equations:
( x + 1 ) 2 [ ( p l ) 2 + ( q m ) 2 ] = ( a l ) 2 + ( b m ) 2 ( x + 1 ) 2 [ ( p a ) 2 + ( q b ) 2 ] = x 2 [ ( a l ) 2 + ( b m ) 2 ]
Find the value of p and q in terms of a , b , x , l and m, provided that x > 0.

Answer & Explanation

rcampas4i

rcampas4i

Beginner2022-10-28Added 22 answers

Divide both equations by ( x + 1 ) 2 and set
α 2 = ( a l ) 2 + ( b m ) 2 ( x + 1 ) 2 β 2 = x 2 [ ( a l ) 2 + ( b m ) 2 ] ( x + 1 ) 2 ,
then the system of equations to solve becomes
{ ( p l ) 2 + ( q m ) 2 = α 2 ( p a ) 2 + ( q b ) 2 = β 2
you have to find the intersection of two circles in the plane. One of these circle has center c 1 = ( l , m ) and radius r 1 = α while the other has center c 2 = ( a , b ) and radius r 2 = β.

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