Rui Baldwin

2020-11-10

For $f\left(x\right)={\mathrm{log}}_{2}x$ between which two integers does f(40) lie? Explain.

Tasneem Almond

f(x) in this case is the exponent you need to raise 2 so that the answer is xx. Since 40 is between 32 and 64 (both powers of 2), then:
$32<40<64$
${2}^{5}<{2}^{f\left(40\right)}<{2}^{6}$
5 So, f(40) is between 5 and 6.

Do you have a similar question?