For f(x)=log2⁡x between which two integers does f(40) lie? Explain.

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For f(x)=log2⁡x between which two integers does f(40) lie? Explain.

Tasneem Almond · Accepted Answer

f(x) in this case is the exponent you need to raise 2 so that the answer is xx. Since 40 is between 32 and 64 (both powers of 2), then:
$32 < 40 < 64$
$2^{5} < 2^{f (40)} < 2^{6}$
5 So, f(40) is between 5 and 6.

For f(x)=log2⁡x between which two integers does f(40) lie? Explain.

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