Exponential growth and decay question A city has a growing population at a rate proportional to the current population, that is: dP/dx=kP. erify that P(t)=P_0e_(kt), t>0 is a solution of the equation. If the population on 1st January 2006 which is t=1 was 147,200 and on 1st January 2007 when t=2 was 154,800, find the initial population and the value of k. Round your answer down to the 3dpl. find the population on 1st January 2012. Find the time it takes for the population to double.

batystowy2b

batystowy2b

Answered question

2022-09-05

Exponential growth and decay question
A city has a growing population at a rate proportional to the current population, that is:
d P d x = k P .
Verify that P ( t ) = P 0 e k t , t > 0 is a solution of the equation.
If the population on 1st January 2006 which is t=1 was 147,200 and on 1st January 2007 when t=2 was 154,800, find the initial population and the value of k. Round your answer down to the 3dpl.
Find the population on 1st January 2012.
Find the time it takes for the population to double.

Answer & Explanation

Bordenauaa

Bordenauaa

Beginner2022-09-06Added 18 answers

Part (ii) has given you two boundary conditions P(1)=147200 and P(2)=154800. Since your general solution has two unknown parameters k and P 0 , you can use the information to find two equations involving them, namely 154800 = P 0 e 2 k , which you can then solve. (Hint: divide). This gives a particular solution to the ODE.
Once you have those, you can evaluate P at the new time given to solve (iii). For (iv), observe that P 0 is the initial population at time t=0, so the population will have doubled at time τ satisfying P ( τ ) = 2 P 0 . You can solve this by taking log of both sides of your particular solution from part (ii).

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