Proving Is mth root of 2 an irrational number for every integer m ≥ 2

Sylvia Byrd

Sylvia Byrd

Answered

2022-07-06

Proving Is mth root of 2 an irrational number for every integer m 2

Answer & Explanation

soosenhc

soosenhc

Expert

2022-07-07Added 16 answers

It's nearly the same:
2 m = a b 2 = a m b m 2 b m = a m a = 2 k 2 b m = ( 2 k ) m    you got to this step 2 b m = 2 m k m b m = 2 m 1 k m b = 2 n
Hence, contradiction, since a and b must be coprime.

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