In the lab, there are two solutions that contain alcohol and Yolanda is mixing them...

Sylvia Byrd

Sylvia Byrd

Answered

2022-07-06

In the lab, there are two solutions that contain alcohol and Yolanda is mixing them with each other. Solution A is 12% alcohol and Solution B is 40% alcohol. She uses 800 milliliters of Solution A. Find how many milliliters of Solution B does she use, if the resulting mixture is a 24% alcohol solution?

Answer & Explanation

Jamiya Costa

Jamiya Costa

Expert

2022-07-07Added 18 answers

Let solution B be V_B
The sum of alcohol in solution A and solution B is equal to the quantity of alcohol in the mixture of solution A and solution B.
Thus, the sum of 12% alcohol in solution A and 40% of alcohol in solution B is equal to the 24% of alcohol in the mixture of solution A and solution B.
12 100 ( V A ) + 40 100 ( V B ) = 24 100 ( V A + V B )
Now, substitute the value of V A = 800 m l in the equation above:
12 100 ( V A ) + 40 100 ( V B ) = 24 100 ( V A + V B )
12 100 ( 800 m l ) + 40 100 ( V B ) = 24 100 ( 800 m l + V B )
96 m l + 40 100 ( V B ) = 192 m l + 24 100 ( V B )
96 m l + 40 100 ( V B ) 96 m l = 192 m l + 24 100 ( V B ) 96 m l
40 100 ( V B ) = 96 m l + 24 100 ( V B )
40 100 ( V B ) 24 100 ( V B ) = 96 m l + 24 100 ( V B ) 24 100 ( V B )
16 100 ( V B ) = 96 m l
100 16 × 16 100 ( V B ) = 100 16 × 96 m l
V B = 600 m l

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get your answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?