Mylo O'Moore

2021-02-22

What is the vertex of the quadratic

Latisha Oneil

Skilled2021-02-23Added 100 answers

Given quadratic equation ,

$y=6{(x-2)}^{2}+10$

On simplifying,

$y=6({x}^{2}+4-4x)+10$

$y=6{x}^{2}-24x+24+10$ (1)

$y=6{x}^{2}-24x+34$

Now, this equation compare with general quadratic equation,

$a{x}^{2}+bx+c$

a = 6 , b = -24 , c = 34

$h=-\frac{b}{2}a$

$=-\frac{-24}{2\cdot 6}$

= 2

Now putting x= 2 in equation (i), then we get

$y=6\cdot {2}^{2}-24\cdot 2+34$

y = 24 - 48 + 34

y = 10

(2, 10) is the vertex of given quadratic equation.

On simplifying,

Now, this equation compare with general quadratic equation,

a = 6 , b = -24 , c = 34

= 2

Now putting x= 2 in equation (i), then we get

y = 24 - 48 + 34

y = 10

(2, 10) is the vertex of given quadratic equation.