Prove 2 + 3 + 5 is an irrational number.

If $\sqrt{2}+\sqrt{3}$ is rational then so too is $\sqrt{2}-\sqrt{3}$ because $(\sqrt{2}+\sqrt{3})\cdot (\sqrt{2}-\sqrt{3})=2-3=-1$
But adding the two terms, $(\sqrt{2}+\sqrt{3})+(\sqrt{2}-\sqrt{3})=2\sqrt{2}$ which is irrational. Two rational numbers cannot sum to an irrational number so we have a contradiction. Therefore $\sqrt{2}+\sqrt{3}$ is irrational. We can say $\sqrt{2}+\sqrt{3}$I and come to the same result/conclusion for $+\sqrt{5}$.
In this case we reach the assumption that I${}^2-5$ is rational.
But I${}^2-5=(\sqrt{2}+\sqrt{3}{)}^2-5=5+2\sqrt{6}-5=2\sqrt{6}$ which is irrational and another contradiction. Hence $\sqrt{2}+\sqrt{3}+\sqrt{5}$ is irrational.