Find the real roots of \(\displaystyle\sqrt{{{x}-{2}}}{\left({x}^{{2}}-{4}{x}+{3}\right)}={0}\) I thought

Brielle James

Brielle James

Answered question

2022-04-08

Find the real roots of x2(x24x+3)=0
I thought the roots of this equation are 1,2,3.
But the teacher says 1 is not a real root because if we take x=1 we get
1(0)
and 1 is not real.

Answer & Explanation

Varikoseocaz

Varikoseocaz

Beginner2022-04-09Added 9 answers

While it is true x=1 is a root, the question is: what is the domain in which the equation "exists"? The answer is that the square root only exists if you consider the inequality x20. Otherwise your solution does not compile, so to speak. So the roots coexisting within your domain are 2 and 3.

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