Given a linear equation pass through the point(6,4) and two axes, and formed a triangle with area 6.

blakkazn924e4y

blakkazn924e4y

Answered question

2022-02-22

Given a linear equation pass through the point(6,4) and two axes, and formed a triangle with area 6. I want to find the equation of that line.
My attempt is letting the equation be y4x6=m. Then using the fact that the area of triangle is 6, forming the equation 12baseheight=6. I got the base and height of the triangle from the axes, base=64m and height=46m
Then substitute the equation 12baseheight=6 and get 36m236m+16=0 which leads to no solution. Can anyone let me know what's wrong?

Answer & Explanation

Jowiszowy9zb

Jowiszowy9zb

Beginner2022-02-23Added 5 answers

You get if calculated correctly 36m260m+16=0
shotokan0758s

shotokan0758s

Beginner2022-02-24Added 8 answers

The equation is given by
y=mx+n
so
y=m(x6)+n
since
P(6;4)
is situated on the line. An both intersection Points are
A(0;46m)
and
P(6m4m,0)
The area our triangle is giveb by
A=12|46m||6m4m|

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