Factoring 4x2−2xy−4x+3y−3Why isn't it working?

blitzbabeiy

blitzbabeiy

Answered

2022-02-01

Factoring 4x22xy4x+3y3
Why isn't it working?

Answer & Explanation

ataill0k

ataill0k

Expert

2022-02-02Added 18 answers

Step 1
When 2x=3, then the expression becomes
4x22xy4x+3y3=93y6+3y3=0
Hence the expression can be factored by (2x3), and you can see easily that
4x22xy4x+3y3=(2x3)(2xy+1)
Emilie Booker

Emilie Booker

Expert

2022-02-03Added 14 answers

Step 1
Probably not the fastest, but I would like to suggest you use the general factorization method:
We have,
4x22xy4x+3y3=4x2x(2y+4)+(3y3)
Δ=(y+2)24(3y3)=(y4)2
x1=y+2+(y4)4=y12
x2=y+2(y4)4=32
4x22xy4x+3y3=4(x32)(xy12)
4x22xy4x+3y3=(2x3)(2xy+1)

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get your answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?