Babenzgs

2022-01-29

Integer between the 's p and $p+2$ is a perfect square. Explain why there exists an integer n such that
$4{n}^{2}-1=p$
a) Is the integer between p and $p+2$ odd or even?
b) Assume additionally that the integer between the 's p and $p+2$ is a perfect square.
c) By considering $\left(2n-1\right)\left(2n+1\right)$, find the only possible value of p.

ocretz56

Step 1
a) If $p=2$ then
$p+2=4$ is not ,

Eliza Norris

Step 1
Given: ${A}^{2}+{B}^{2}={C}^{2}$ the most common means of generating Pythagorean triples is Euclids

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