Solve the following equations and inequalities: 1) -x^2+2x>1 2) |1-3x|=5 3) |4x-3|\leq2

trefoniu1

trefoniu1

Answered question

2022-01-24

Solve the following equations and inequalities:
1) x2+2x>1
2) |13x|=5
3) |4x3|2

Answer & Explanation

terorimaox

terorimaox

Beginner2022-01-25Added 16 answers

a)x2+2x>1
x2+2x1>0
(x22x+1)>0
x22x+1<0
(x1)2<0
Square of any number cannot be negative.Thus, there is no solution.

Aiden Cooper

Aiden Cooper

Beginner2022-01-26Added 14 answers

Consider the part (2):
|13x|=5
±(13x)=5
13x=5
3x=4
x=43
(13x)=5
1+3=5
3x=6
x=2
Hence, the solution is x=43,2
Consider the part (3):
|43x|2
±(43x)2
43x2
3x2
3x2
x23
(43x)2
4+3x2
3x6
x2
Thus, the solution is x=[23,2]

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?