Rewrite expression without absolute value bars. |7−π|

Question

Rewrite expression without absolute value bars.  |7−π|

Theodore Schwartz · Accepted Answer

Step 1 The given expression is |7−π|. Absolute value: The algebraic definition of absolute value is as follows: |a|={aifa≥0−aifa&amp;lt;0 Step 2 Now, 7−π&amp;gt;0 |7−π|=7−π or approximately 3.858 The absolute value of a positive number is the number within the absolute value bars.

Accepted Answer

7-3.1415926

Mr Solver · Accepted Answer

Result:7−π if 7−π≥0or−(7−π) if 7−π&amp;lt;0Solution:To rewrite the expression |7−π| without absolute value bars, we need to consider two cases: when the expression inside the absolute value bars is positive and when it is negative.Case 1: When 7−π is non-negative (greater than or equal to zero):In this case, |7−π| simplifies to the expression itself, so we can write it as:7−πCase 2: When 7−π is negative:In this case, the expression inside the absolute value bars becomes its negation. Therefore, we can write it as:−(7−π)Combining both cases, we can rewrite the expression |7−π| without absolute value bars as:7−π if 7−π≥0or−(7−π) if 7−π&amp;lt;0

Nick Camelot · Accepted Answer

Case 1: When 7−π is positive:In this case, we can rewrite |7−π| as simply (7−π).|7−π|=(7−π)=7−πCase 2: When 7−π is negative:In this case, the expression |7−π| becomes −(7−π), as the absolute value of a negative number is the positive value of that number.|7−π|=−(7−π)=−7+πHence, the expression |7−π| can be rewritten as the sum of two cases:|7−π|={7−π,if&amp;nbsp;7−π≥0−7+π,if&amp;nbsp;7−π&amp;lt;0Now, substituting the value of π with its approximate value (π≈3.14159), we can calculate the final result:|7−π|={7−3.14159,if&amp;nbsp;7−3.14159≥0−7+3.14159,if&amp;nbsp;7−3.14159&amp;lt;0Calculating the two cases:Case 1: When 7−3.14159≥0:7−3.14159=3.85841Case 2: When 7−3.14159&amp;lt;0:−7+3.14159=−3.85841Therefore, the final result is 3.858.

madeleinejames20 · Accepted Answer

To rewrite the expression without absolute value bars,

| 7 - π |

, we need to consider the cases when the expression inside the absolute value is positive and when it is negative.
Case 1: When

7 - π

is positive, the expression simplifies to

7 - π :

| 7 - π | = 7 - π

Case 2: When

7 - π

is negative, the expression simplifies to

- (7 - π) :

| 7 - π | = - (7 - π)

Combining both cases, we can write the expression without absolute value bars as follows:

| 7 - π | = {\begin{matrix} 7 - π, & if 7 - π \geq 0 \\ - (7 - π), & if 7 - π < 0 \end{matrix}

Rewrite expression without absolute value bars. abs(7- pi)

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