ndimiimpercea2

2022-01-21

To determine:
$-10{x}^{2}+30x-20=0$?

Kudusind

Expert

Step 1
Given: $-10{x}^{2}+30x-20=0$
Multiplying both sides with -1
We get,
$10{x}^{2}-30x+20=0$
$x=\frac{-b±\sqrt{{b}^{2}-4ac}}{2a}$
we get,
$⇒x=\frac{30±\sqrt{{30}^{2}-4×10×20}}{2×10}$
$⇒x=\frac{30±10}{20}$

Thus we get the value of x as

Expert

Step 1
Given:
$-10{x}^{2}+30x-20=0$
$-10\left({x}^{2}-3x+2\right)=0$
Dividing both sides by 10 we get
${x}^{2}-3x+2=0$
${x}^{2}-x-2x+2=0$
$x\left(x-1\right)-2\left(x-1\right)=0$
$\left(x-2\right)\left(x-1\right)=0$
$x-2=0$
$x=2$ NKS $x-1=0$
$x=1$

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